 |
28 |
|
You would be right if this molecule would be rigid. In that case one of
the signals from the methyl group should arise from
H1, and the second signal - with twice
the intensity - should arise from H2
and H3.
However, the methyl protons in acetealdehyde show at room
temperature only a single, shared signal. That is, the methyl protons
have the same electronic environment and have the same chemical shift.
Try to come up with an explanation for the observation and compare your
answer with the official solution.
(Hint: Is the shown structure the only possible conformation for
acetealdehyde?)
|
|
|
|
|
